Let $A$ and $B$ be an $n \times n$ matrices.
Suppose that all the eigenvalues of $A$ are distinct and the matrices $A$ and $B$ commute, that is $AB=BA$.
Then prove that each eigenvector of $A$ is an eigenvector of $B$.
(It could be that each eigenvector is an eigenvector for distinct eigenvalues.)Add to solve later