No Finite Abelian Group is Divisible
Problem 240
A nontrivial abelian group $A$ is called divisible if for each element $a\in A$ and each nonzero integer $k$, there is an element $x \in A$ such that $x^k=a$.
(Here the group operation of $A$ is written multiplicatively. In additive notation, the equation is written as $kx=a$.) That is, $A$ is divisible if each element has a $k$-th root in $A$.
(a) Prove that the additive group of rational numbers $\Q$ is divisible.
(b) Prove that no finite abelian group is divisible.
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