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		<title>Row Equivalence of Matrices is Transitive</title>
		<link>https://yutsumura.com/row-equivalence-of-matrices-is-transitive/</link>
				<comments>https://yutsumura.com/row-equivalence-of-matrices-is-transitive/#respond</comments>
				<pubDate>Mon, 25 Dec 2017 04:14:23 +0000</pubDate>
		<dc:creator><![CDATA[Yu]]></dc:creator>
				<category><![CDATA[Linear Algebra]]></category>
		<category><![CDATA[elementary row operations]]></category>
		<category><![CDATA[linear algebra]]></category>
		<category><![CDATA[row equivalent]]></category>
		<category><![CDATA[transitive]]></category>

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				<description><![CDATA[<p>If $A, B, C$ are three $m \times n$ matrices such that $A$ is row-equivalent to $B$ and $B$ is row-equivalent to $C$, then can we conclude that $A$ is row-equivalent to $C$? If&#46;&#46;&#46;</p>
<p>The post <a href="https://yutsumura.com/row-equivalence-of-matrices-is-transitive/" target="_blank">Row Equivalence of Matrices is Transitive</a> first appeared on <a href="https://yutsumura.com/" target="_blank">Problems in Mathematics</a>.</p>]]></description>
								<content:encoded><![CDATA[<h2> Problem 642</h2>
<p>If $A, B, C$ are three $m \times n$ matrices such that $A$ is row-equivalent to $B$ and $B$ is row-equivalent to $C$, then can we conclude that $A$ is row-equivalent to $C$?  </p>
<p>If so, then prove it.  If not, then provide a counterexample.</p>
<p>&nbsp;<br />
<span id="more-6309"></span></p>
<h2>Definition (Row Equivalent).</h2>
<p>Two matrices are said to be <strong>row equivalent</strong> if one can be obtained from the other by a sequence of elementary row operations.</p>
<h2>Proof.</h2>
<p>Yes, in this case $A$ and $C$ are row-equivalent. </p>
<p>By assumption, the matrices $A$ and $B$ are row-equivalent, which means that there is a sequence of elementary row operations that turns $A$ into $B$. </p>
<p>Call this sequence $r_1 , r_2 , \cdots , r_n$, where each $r_i$ is an elementary row operation.<br />
(Start with applying $r_1$ to $A$.)</p>
<p>By another assumption, $B$ is row-equivalent to $C$, which means that there is a sequence of elementary row operations which transforms $B$ into $C$; call this sequence $s_1 , s_2 , \cdots , s_m$. </p>
<p>Putting these sequences together, the operations $r_1 , r_2 , \cdots , r_n$ , $s_1 , s_2 , \cdots , s_m$ will transform the matrix $A$ into $C$. </p>
<p>This proves that $A$ and $C$ are row-equivalent.	</p>
<button class="simplefavorite-button has-count" data-postid="6309" data-siteid="1" data-groupid="1" data-favoritecount="17" style="">Click here if solved <i class="sf-icon-star-empty"></i><span class="simplefavorite-button-count" style="">17</span></button><p>The post <a href="https://yutsumura.com/row-equivalence-of-matrices-is-transitive/" target="_blank">Row Equivalence of Matrices is Transitive</a> first appeared on <a href="https://yutsumura.com/" target="_blank">Problems in Mathematics</a>.</p>]]></content:encoded>
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