# An excess of hydrochloric acid was added to 300.00 g of potassium carbonate.

**An excess of hydrochloric acid was added to 300.00 g of potassium carbonate. Determine the mass of the salt obtained and the volume of gas evolved.**

To solve the problem, let’s compose an equation, arrange the coefficients:

CaCO3 + 2HCl = CaCl2 + H2O + CO2 – exchange reaction, obtained salt calcium chloride, carbon dioxide;

Let’s make calculations using the formulas:

M (CaCO3) = 100 g / mol;

M (CaCl2) = 111 g / mol;

M (CO2) = 44 g / mol.

Determine the amount of moles of calcium carbide:

Y (CaCO3) = m / M = 300/100 = 3 mol.

According to the reaction equation, the amount of moles of calcium carbonate and calcium chloride is 1 mole, which means that Y (CaCl2) = 3 moles.

We calculate the mass of the CaCl2 salt by the formula:

m (CaCl2) = Y * M = 3 * 111 = 333 g.

We find the volume of carbon dioxide, taking into account the data of the reaction equation:

Y (CO2) = 3 mol;

V (CO2) = 3 * 22.4 = 67.2 liters.

Answer: the mass of calcium chloride is 333 g, the volume of carbon dioxide is 67.2 liters.