Rank and Nullity of Linear Transformation From $\R^3$ to $\R^2$
Problem 369
Let $T:\R^3 \to \R^2$ be a linear transformation such that
\[ T(\mathbf{e}_1)=\begin{bmatrix}
1 \\
0
\end{bmatrix}, T(\mathbf{e}_2)=\begin{bmatrix}
0 \\
1
\end{bmatrix}, T(\mathbf{e}_3)=\begin{bmatrix}
1 \\
0
\end{bmatrix},\]
where $\mathbf{e}_1, \mathbf{e}_2, \mathbf{e}_3$ are the standard basis of $\R^3$.
Then find the rank and the nullity of $T$.
(The Ohio State University, Linear Algebra Exam Problem)
Add to solve later
Sponsored Links
Solution.
The matrix representation of the linear transformation $T$ is given by
\[A=[T(\mathbf{e}_1), T(\mathbf{e}_2), T(\mathbf{e}_3)]=\begin{bmatrix}
1 & 0 & 1 \\
0 &1 &0
\end{bmatrix}.\]
Note that the rank and nullity of $T$ are the same as the rank and nullity of $A$.
The matrix $A$ is already in reduced row echelon form.
Thus, the rank of $A$ is $2$ because there are two nonzero rows.
Another way to see this is to use the leading 1 method. It implies that the first two columns vectors form a basis of the range of $A$ because the first two columns contain the leading 1’s.
Thus, the rank (=the dimension of the range) is $2$.
The rank-nullity theorem says that
\[\text{rank of $A$} + \text{ nullity of $A$}=3 \text{ (the number of columns of $A$)}.\]
Hence the nullity of $A$ is $1$.
In summary, the rank of $T$ is $2$, and the nullity of $T$ is $1$.
Linear Algebra Midterm Exam 2 Problems and Solutions
- True of False Problems and Solutions: True or False problems of vector spaces and linear transformations
- Problem 1 and its solution: See (7) in the post “10 examples of subsets that are not subspaces of vector spaces”
- Problem 2 and its solution: Determine whether trigonometry functions $\sin^2(x), \cos^2(x), 1$ are linearly independent or dependent
- Problem 3 and its solution: Orthonormal basis of null space and row space
- Problem 4 and its solution: Basis of span in vector space of polynomials of degree 2 or less
- Problem 5 and its solution: Determine value of linear transformation from $R^3$ to $R^2$
- Problem 6 and its solution (current problem): Rank and nullity of linear transformation from $R^3$ to $R^2$
- Problem 7 and its solution: Find matrix representation of linear transformation from $R^2$ to $R^2$
- Problem 8 and its solution: Hyperplane through origin is subspace of 4-dimensional vector space
Add to solve later
Sponsored Links
4 Responses
[…] Problem 6 and its solution: Rank and nullity of linear transformation from $R^3$ to $R^2$ […]
[…] Problem 6 and its solution: Rank and nullity of linear transformation from $R^3$ to $R^2$ […]
[…] Problem 6 and its solution: Rank and nullity of linear transformation from $R^3$ to $R^2$ […]
[…] Problem 6 and its solution: Rank and nullity of linear transformation from $R^3$ to $R^2$ […]